A 4X4 square is centered on the origin. It is dilated by a factor of 2. What are the coordinates of the vertices of the new square? Options:
A’(4, 4), B’(4, -4), C’(-4, -4), D’(-4, 4)
A’(2, 2), B’(2, -2), C’(-2, -2), D’(-2, 2)
A’(8, 8), B’(8, -8), C’(-8, -8), D’(-8, 8)
A’(½, ½), B’(½, -½), C’(-½, -½), D’(-½, ½)

not solvable

step-by-step explanation:

we need more information, or at least an

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.