100 POINTS Choose all the quadratic pairs that are equivalent. 1 2 (x + 4)2 = 2 x2 + 8x + 15 = 0 (x − 5)2 = 1 x2 − 10x + 26 = 0 3(x − 1)2 + 5 = 0 3x2 − 6x + 8 =

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: