For which function and interval can the extreme value theorem be applied? f (x) = StartFraction x Over (x minus 6) squared EndFraction over the interval [3, 5]
f (x) = StartFraction negative 5 Over 2 (x minus 7) cubed EndFraction over the interval (6, 8)
f(x) = 4 tan(πx) over the interval [0, 1]
f(x) = 3ex + 1 over the interval (1, 3)

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

a variable is any characteristics, number, or quantity that can be measured or counted. a variable may also be called a data item. hope i !

step-by-step explanation:

deez nut

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term