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Mathematics, 10.05.2021 06:10 babowmanjacob666
Solve the equation on the
interval [0, 2pi).
4(sin x)^2 – 2 = 0
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Answers: 2
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You know the right answer?
Solve the equation on the
interval [0, 2pi).
4(sin x)^2 – 2 = 0
...
interval [0, 2pi).
4(sin x)^2 – 2 = 0
...
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