12. A seismologist positions two recording devices 340 feet apart at points A and B. To check the calibration, an explosive is detonated between the devices 90 feet from point A. The time the
explosions register on the devices is noted and the difference calculated. A second explosion will
be detonated cast of point A. How far cast should the second explosion be positioned so that the
measured time difference is the same as for the first explosion? (Hint: 1 mile - 5280ft, sound
travels at approximately 1100 ft/sec)

0.038

step-by-step explanation:

answer: get a conversion sheet out i dont know the exact measurments

step-by-step explanation: divide the number of feet with the nu,ber of milrs and there your answer

- click here to get an answer to your question ✍ 75 i will mark one of the angles formed by two

step-by-step explanation:

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: