___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb
B. Sina
C. Cosb
D. Cosa
...
Mathematics, 10.05.2021 18:40 robert7248
___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb
B. Sina
C. Cosb
D. Cosa
![___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb
B. Sina
C. Cosb
D. Cosa](/tpl/images/2343/9255/9e504.jpg)
Answers: 2
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