The answer is the first or last option but I don’t know which one

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Cody was 165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.

Solve the system of equations. x=-2y+1 and x+2y=9. show work