There’s a group of four A, C, MO, and MA
Construct a pattern that ends at 24, allowing each to get 6 turns. The pattern must also make sure that either A or MO always land on 1, 2, 12, 13, 18, and 19.

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%