Suppose that you are taking a course that has four tests. The first three tests are each worth 20% of the course grade, and the fourth test is worth 40% of the grade. To get a B in the course, you must have an overall average of at least 80%.

Your grades on the first three tests were: Test 1 =
86
%, Test 2 =
98
%, and Test 3 =
72
%.

What is the minimum score you need on the fourth test to get a B in the course?.

Your answer is:
%
(Round to at least 1 decimal place)

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

0.02040816326

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

brainliest lol i just need one more brainliest.

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)