Please help Clare is deriving the quadratic formula by solving ax^2+bx+c=0 by completing the square.
She arrived at this equation:
(2ax+b)^2=b^2-4ac
Briefly describe what she needs to do to finish solving for I and then show the steps.

Clare starts with:

a*x^2 + b*x + c = 0

And she gets to:

(2*a*x + b)^2 = b^2 - 4*a*c

Now we want to show the final steps to solve the equation (isolating x)

First, we apply the square root to both sides:

Because the square root has two solutions, (one negative and one positive), we will write:

Now we subtract b in both sides:

Now let's divide by 2*a in both sides:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: