Two different banks, Bank A and Bank B, offer accounts with exactly the same annual interest rate of 6.85%. However, the account from Bank A has interest compounded monthly, whereas the account from Bank B compounds interest continuously. To decide which bank to open an account with, you calculate the amount of interest you would earn after three years from an initial deposit of $5000 in each bank’s account. How much interest would you earn from each account? Which bank’s account earns more – and how much more?

Sorry don't know

Solution given:

For bank A.

rate[R]=6.85%

principal [P]=$5000

time [T]=3years

now since simple interest is given by this bank

we have

Simple interest=PTR/100

=5000×6.85×3/100=$1027.5

For bank B

rate[R]=6.85%

principal [P]=$5000

time [T]=3years

now since compound interest is given by this bank

we have

compound interest=P((1+R/100)^T-1)

=$5000((1+6.85/100)³-1)=$1099.49

since

Bank B gives more interest .more amount is

1099.49-1027.5=$71.99 or $72

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier