Which relationship is true for the triangle based on the Law of Sines? $\frac{\sin100\degree}{10}=\frac{\s in B}{100}$ $\frac{\sin100\degree}{6}=\frac{\si n C}{7}$ $\frac{\sin100\degree}{6}=\frac{\si n B}{10}$ $\frac{\sin100\degree}{10}=\frac{\s in C}{6}$