What is the Ka of a solution of 0.025M formic acid, if the pH 10 points is 2.60? Answers
Ka = 0.025
Ka = 2.5x10^-4
Ka = 2.8x10^-4
Ka = 2.8x10^-2

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Which expression do you get when you eliminate the negative exponents of 4a^2 b^216a^-3 b

For the quadratic function [tex]y=(x+4)^2-1[/tex] , do the following: a) rewrite the function in the standard form, b) rewrite the function in intercept form, c) find the vertex, d) find the y-intercept, e) find the x-intercepts.