In \triangle CDF, m\angle D=90\deg, m\angle C=29\deg△CDF, m∠D=90deg, m∠C=29deg and the length of the hypotenuse is 10 units. Using this information below, what is the length of CDCD? 5.5 units 4.8 units 8.7 units 2.9 units

8 units

Step-by-step explanation:

Given

Hypotenuse CF = 10

m<C = 29degrees

m<D = 90degrees

m<F = 180 - (29+90)

m<F = 180 - 119

m<F = 61degrees

Since the side facing <F is CD, then;

Opposite = CD

using the SOH CAH TOA identity

sin 61 = opp/hyp

sin61 = CD/10

CD = 10sin61

CD = 10(0.8746)

CD = 8.746

Hence the length of CD is 8 units

it is c, trust i got your back lol

step-by-step explanation: