One number is equal to the square of another. Find the numbers if both are positive and their sum is 90.

x = y^2

:

Find the numbers if both are positive and their sum is 12

x + y = 12

replace x with y^2, you have a quadratic equation

y^2 + y - 12 = 0

Step-by-step explanation:

Factors to

(y+4)(y-3) = 0

The positive solution is all they want here

y = 3

then

x = 3^2

x = 9

;

they add up to 12

I’m a bit confused by the question, but hope this helps. Look below!

Step-by-step explanation:

There are multiple different ones, but here’s the ones I think. (This is my work btw.)

45+45= 90

45•45= not 45

10+80=90

10•10= not 80

9+81= 90

9•9=81

9 and 81!

step-by-step explanation:

differentiate (x^14(x^-2)^4with respect to the variable

the parentheses don't balance in your input.

differentiate 0 with respect to

the final answer is

0

hope this