PLEASE Hurry If f(x)=7x2−2 and g(x)=2(x−7)2 , which is an equivalent form of f(x)−g(x) ? A 5x2−100 B 5x2+28x−100 C 5x2+14x−51 D 3x2+56x−198

Step-by-step explanation:

PLEASE Hurry If f(x)=7x2−2 and g(x)=2(x−7)2 , which is an equivalent form of f(x)−g(x) ? A 5x2−100 B 5x2+28x−100 C 5x2+14x−51 D 3x2+56x−198

5x^2 +28x - 100

Step-by-step explanation:

f(x)=7x^2−2 and g(x)=2(x−7)^2

First simplify g(x)

g(x) = 2 ( x-7)(x-7) = 2( x^2 - 7x -7x +49) = 2(x^2 -14x +49) = 2x^2 -28x +98

Now f(x) - g(x)

f(x) - g(x) = 7x^2−2 - (2x^2 -28x +98)

Distribute the minus sign

            = 7x^2−2 - 2x^2 +28x -98

Combine like terms

            = 5x^2 +28x - 100

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

x = 3 ± √(5+y)