What is the equation of a circle with center (-2,3) and radius 4? A. (x + 2)2 +- 3)2 = 16 O B. (x + 2)2 + (y - 3)2 = 4 O C. (x-2)2 + (y + 3)2 = 16 D. (x + 2)2 = (y - 3)2 = 16​

(x+2)^2 + (y-3)^2 = 4^2

(x+2)^2 + (y-3)^2 = 16

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15