At the end of her work day at the Ferguson Corporation, Sarah usually walks to the subway station to travel home. Today, she is walking to the

Springdale Town Center first to take care of some errands. She will then

continue walking to the subway station to travel home. The map of these

routes is shown below.

2000 feet

Subway

Ferguson

Corporation

Station

Springdale

Town Center

If Sarah walks to the Springdale Town Center from the Ferguson

Corporation and then to the Subway Station, how much farther will she

walk than if she walks directly to the Subway Station from the Ferguson

Corporation? Show all of your work.

1263.7032 feets

Step-by-step explanation:

Distance from Ferguson corporation to Springdale Town center ; let the distance = x

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 27 = x / 2000

0.5095254 * 2000 = x

1019.0508 feets

Distance from Springdale to Subway station, this is the hypotenuse :

Hypotenuse = √(1019.0508² + 2000²)

Hypotenuse = √5038464.7

Hypotenuse = 2244.6524 feets

Total distance walked from Ferguson to Springdale, then to Subway ;

(1019.0508 + 2244.6524) feets = 3263.7032 feets

Additional distance walked :

(3263.7032 feets - 2000 feets) = 1263.7032

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.