Solve the following system of equations algebraically:
y = x^2 – 10x + 15
y = 2x – 5

(2, -1)

(10, 15)

Step-by-step explanation:

Subtract the second equation from the first

  y = x² – 10x + 15

- (y =           2x – 5)

————————————

 0 = x² - 12x + 20

Factor

(x  - 2)(x - 10) = 0

x = {2, 10}

For x = 2

y = 2(2) - 5

y = -1

Solution 1

(2, -1)

For x = 10

y = 2(10) - 5

y = 15

Solution 2

(10, 15)

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step-by-step explanation:

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