Tuning standard A has a frequency of 440 cycles per second, or Hertz. The frequency of a musical note, in Hertz, can be given by f(x) = 440(2x), where x is the number of octaves above the tuning standard A. How many octaves above the tuning standard A is a note that has frequency 1,397 Hertz? Give an exact solution as a logarithm.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

the first one

step-by-step explanation:

just id the test.