In a math class with 19 students, a test was given the same day that an assignment was due. There were 12 students who passed the test and 13 students who completed
the assignment. There were 4 students who failed the test and also did not complete
the assignment. What is the probability that a student completed the homework given
that they passed the test?

Work Shown:

With a class total of 19, we know that A+B+C+D = 19.

12 students passed the test, which leaves 19-12 = 7 people who failed the test.

Of these 7 people who failed the test, 4 of them didn't do the hw. This leads to D = 4.

Note how C+D = 7 becomes C+4 = 7 and it solves to C = 3.

Since 13 people did the hw, we can say A+C = 13. Plug in that value of C we found earlier, to find that A = 10.

Lastly, solving A+B = 12 leads to B = 2.

To summarize what we found so far:

Now onto the question your teacher is asking: "What is the probability that a student completed the homework given that they passed the test?"

The key phrase here is "given that they passed the test". Because of this phrase, we'll ignore anyone who didn't pass. We'll focus solely on the 12 students who passed. Of those 12 who passed, we found that A = 10 people did the hw.

Therefore, the probability of picking someone who did the hw, given the passed the test, is 10/12 = 5/6

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .

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step-by-step explanation: