A barrel contains 56 litres of kerosene. It has two taps. One tap draws 500 ml every 6 minutes. After first 5 litres are drawn from the barrel, the second tap also starts. It draws 1 litre in every 5 minutes. How many hours will be taken in all to empty the tank?​

The tank will empty in 4 hours.

Step-by-step explanation:

Since a barrel contains 56 liters of kerosene, and it has two taps, one tap that draws 500 ml every 6 minutes and after first 5 liters are drawn from the barrel, the second tap also starts, and it draws 1 liter in every 5 minutes, to determine how many hours will be taken in all to empty the tank, the following calculation must be performed:

0.5 x X = 5

X = 5 / 0.5

X = 10

10 x 6 = 60

1 hour = 51 liters

1 hour 30 minutes = 51 - (1 x 6) - (0.5 x 5) = 42.5

2 hours = 42.5 - (1 x 6) - (0.5 x 5) = 34

2 hours 30 minutes = 34 - (1 x 6) - (0.5 x 5) = 25.5

3 hours = 25.5 - (1 x 6) - (0.5 x 5) = 17

3 hours 30 minutes = 17 - (1 x 6) - (0.5 x 5) = 8.5

4 hours = 8.5 - (1 x 6) - (0.5 x 5) = 0

Therefore, the tank will empty in 4 hours.