The ages in years of 10 teachers of a school are : 32, 41, 28, 54, 35, 26, 23, 33, 38, 40. What is the range of ages of the teachers?

Step-by-step explanation:

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step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47