Find the probability of each event. A politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important. Just before the speech, she drops all of the cards and picks them up in a random order. What is the probability that cards #1, #2, and #3 are still in order on the top of the stack?

The probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.

Step-by-step explanation:

Since a politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important, and just before the speech, she drops all of the cards and picks them up in a random order, to determine what is the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack, the following calculation must be performed:

1/13 x 1/13 x 1/13 = X

0.076 x 0.076 x 0.076 = X

0.00045 = X

0.00045 x 100 = 0.045

Therefore, the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23