The length of one leg of a right triangle is 20.3 centimeters. The length of the hypotenuse is 30.7 centimeters. Which is closest to the length of the other leg?

Work Shown:

a = 20.3

b = unknown

c = 30.7

Apply the pythagorean theorem to find b

a^2 + b^2 = c^2

(20.3)^2 + b^2 = (30.7)^2

412.09 + b^2 = 942.49

b^2 = 942.49-412.09

b^2 = 530.4

b = sqrt(530.4)

b = 23.0304146727757  value is approximate

b = 23.0

I rounded to one decimal place because the other values (20.3 and 30.7) were to one decimal place.

answer: it is d

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1