The rectangle below has an area of 70y^8 + 30y^6. The width of the rectangle is equal to the greatest common monomial factor of 70y^8 and 30y^6. What is the length and width of the rectangle?​

Length: 7y^2+3

Width: 10y^6

Step-by-step explanation:

Given that the rectangle has an area of 70y^8 + 30y^6.

The width of the rectangle is equal to the greatest common monomial factor of 70y^8 and 30y^6.

First let us get the width;

70y^8 = 7 * 10 * y^2 * y^6

30y^6 = 3 * 10 * y^6

Since 10y^6 is common to both factors, hence the width of the rectangle will be 10y^6

Given;

Area = Length * width

A(x) = W(x)*L(x)

A(x) = 70y^8 + 30y^6

A(x) =  10y^6(7y^2+3)

On comparison

L(x) = 7y^2+3

Hence length is 7y^2+3 and width is 10y^6

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant