PLEASE HELP ME WITH THIS

You may use cos 60° or sin 30°. Let's use cos 60°.

cos 60° = opp/hyp = (2 mm)/j

or

j = (2 mm)/(cos 60°) = 4 mm

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine