Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36 ducks for $532

★ Given :

Cost of 50 chickens and 30 ducks = $ 550

Cost of 44 chickens and 36 ducks = $ 532

★ To find :

Cost of chicken and duck

★ Solution :

Assume :

Cost of chicken = x

Cost of duck = y

According to question :

50x + 30y = 550 (1)

44x + 36y = 532(2)

1) - (2)

(50x + 30y) - (44x + 36y) = 550 - 532

50x + 30y - 44x - 36y = 18

6x - 6y = 18

6(x - y) = 18

x - y = 18/6

→ x - y = 3 (3)

In equation 1 ,

50 x + 30y = 550

taking 10 common

10(5x + 3y) = 550

5x + 3y = 550/10

5x + 3y = 55

by taking 3 common

3(5/3 x + y) = 55

by dividing 3 on both sides

5/3x + y = 55/3 (4)

(3) + (4)

x - y + 5/3 x + y = 3 + 55/3

x + 5/3 x = 64/3

8/3 x = 64/3

by multiplying 3 on both sides

8x = 64

x = 64/8

→ x = 8

→ Cost of chicken = $ 8 ..

by putting value of x in equation 3

x - y = 3

8 - y = 3

y = 8 - 3

→ y = 5

→ Cost of ducks = $5..

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