A circle is graphed on this coordinate plane. What is the radius in units of the circle and what is the equation of the circle?​

The radius is 4 units, and the equation of the circle is:

(x - 3)^2 + (y + 5)^2 = 16

Step-by-step explanation:

A circle centered at the point (a, b) and with a radius R, is written as:

(x - a)^2 + (y - b)^2 = R^2

In the image, we can see that a segment that cuts the circle in two halves is the segment between the points:

(-1, -5) and (7, - 5)

The distance between these points is the diameter of the circle.

Remember that the distance between two points (x₁, y₁) and (x₂, y₂) is:

D = √( (x₂ - x₁)^2 + (y₂ - y₁)^2)

Then in this case, the distance between the known points is:

D = √( (7 - (-1))^2 + (-5 - (-5))^2)

D = √( 8^2) = 8

The diameter of the circle is 8

Then the radius is:

R = 8/2 = 4

the radius is 4.

Now, to find the center of the circle we just need to go to any of the two extremes of the interval and count 4 units towards the center of the circle, this is:

(-1 + 4, -5) = (3, -5)

or

(7 - 4, -5) = (3, -5)

Then the center of the circle is the point (3, -5) and the radius is R = 4

The equation of the circle is:

(x - 3)^2 + (y - (-5))^2 = 4^2

(x - 3)^2 + (y + 5)^2 = 16

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.