Translate the word problem into an equation and solve algebraically. Include correct units. The length of a rectangular area is 4 feet more than its width. If the area is 45 square feet, find the length and the width of the
rectangle.

Step-by-step explanation:    TS 5 15 8 26

L = W + 4

Area = 45 ft²

Area = LW

Area = (W +4)(W) = 45 ft²

         W² + 4W - 45 = 0        solve for W

         (W + 9)(W - 5) = 0

         W = -9 or 5                a minus 9 width makes no sense

     L = W + 4

     L = 5 + 4

W = 5 ft   L = 9 ft

right

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18