A chemist has three different acid solutions. The first solution contains 20%
acid, the second contains 30% acid and
the third contains 50% acid. He wants to
use all three solutions to obtain a mixture
of 80 liters containing 40% acid, using
three times as much of the 50% solution
as the 30% solution. How many liters of
each solution should be used?
A. x=16, y=16, z=48
B. x=16, y = 48, z=16
C. x=24, y=14, z=42
D. X=16, y=24, z = 40