A gaming company would like to test the hypothesis that the average age of someone who uses gaming console A is different from the average age of someone who uses gaming console B. A random sample of 36 gaming console A users had an average age of 34.2 years while a random sample of 30 gaming console B users had an average age of 32.7 years. Assume that the population standard deviation for the age of gaming console A and gaming console B users is 3.9 and 4.0​ years, respectively. This company would like to set α = 0.10. a) What is the critical value for this hypothesis​ test?
a) 2.33
b) 1.28
c) 1.645
d) 1.96
b) What is the 90% confidence interval for the difference in population means?
a) (-0.11, 3.11)
b) (-1.70, 4.70)
c) (0.65, 2.35)
d) (1.18, 1.82)

Question a:

c) 1.645

Question b:

a) (-0.11, 3.11)

Step-by-step explanation:

Before answering the question, we need to understand the central limit theorem and subtraction between normal variables:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A random sample of 36 gaming console A users had an average age of 34.2 years, with a standard deviation of 3.9 years.

This means that

A random sample of 30 gaming console B users had an average age of 32.7 years, with a standard deviation of 4 years.

This means that

Distribution of the difference in population means:

a) What is the critical value for this hypothesis​ test?

We test if the means are different, which means that we have a two-tailed test.

We have the standard deviations for the population, which means that we have a Z test.

Since it is a two-tailed Z-test, the critical value is Z with a p-value of 1 - (0.1/2) = 1 - 0.05 = 0.95, so, looking at the z-table, Z = 1.645, which is option C.

b) What is the 90% confidence interval for the difference in population means?

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

That is z with a pvalue of , so Z = 1.645.

Now, find the margin of error M as such

The lower end of the interval is the sample mean subtracted by M. So it is 1.5 - 1.61 = -0.11

The upper end of the interval is the sample mean added to M. So it is 1.5 + 1.61 = 3.11

The correct answer is given by option A.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

found it xd it ok yt