Please help me... :)

Part 1

There are many ways to go about this, but one possibility is the following:

You are building a tree house. Your ladder is 10 feet long and the portion in the tree you're trying to get to is 8 feet off the ground. How far should the base of the ladder be from the tree so you can reach that portion?

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Part 2

The drawing is shown below. The diagram is shown in 2D to keep things as simple as possible. Adding a third dimension greatly complicates everything.

We have a right triangle, so it has a 90 degree angle as shown by the square marker. The vertical leg is 8 feet. The horizontal leg is unknown. The hypotenuse (longest side) is 10 feet long to indicate the ladder.

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Part 3

Use the pythagorean theorem to get...

a^2 + b^2 = c^2

x^2 + 8^2 = 10^2

x^2 + 64 = 100

x^2 = 100-64

x^2 = 36

x = sqrt(36)

x = 6

The base of the ladder should be 6 feet away from the tree, so that you can reach 8 feet off the ground.

l.ln.lln.k.nkl

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841