The temperature of the first 6 days in march is shown below. if the temperature 23 F is removed from below, how much greater is the range of the original 6 temperatures than the range of the 5 temperatures: 23F 58F 62F 64F 64F 65F
a. 35
b. 42
c. 7
d. 23

Given:

The temperature of the first 6 days in march is:

23F, 58F, 62F, 64F, 64F, 65F

23 F is removed from the data set.

To find:

How much greater is the range of the original 6 temperatures than the range of the 5 temperatures.

Solution:

Range of a data set is:

Range = Maximum value - Minimum value

The given data set is:

23 F, 58 F, 62 F, 64 F, 64 F, 65 F

The range of given data set is:

Range = 65 - 23

           = 42

If the temperature 23 F is removed from the data set, then the new data set is:

58 F, 62 F, 64 F, 64 F, 65 F

The range of this new data set is:

Range = 65 - 58

           = 7

Now, the difference between original range and new range is:

The original range is 35 more than the new range. Therefore, the correct option is a.

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation:

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)