Math problem 16.

Find the value of x, y and z.

sqrt. 244

Step-by-step explanation:

a^2 + b^2 =c^2

10^2 + 12^2 =244

c^2 =244

c= sqrt. 244

if x+y equal 90

and z equal 2 sqrt 61

if you want the real values of the x and y iam not sure but you have to use ratios and proportions Formula for example 24k=90

k =15/4

y=10k

x=12k

like this hopefully its helpful

the answer would be 44.79

plz mark brainliest

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)