Factor the expression. 10g3 + 15g2 – 12g – 18

(5g2 + 6)(2g – 3)

(5g2 + 3)(2g – 6)

(5g2 – 3)(2g + 6)

(5g2 – 6)(2g + 3)

Suppose you are choosing a 6-digit personal access code. this code is made up of 4 digits chosen from 1 to 9, followed by 2 letters chosen from a to z. any of these digits or letters can be repeated. find the total number of personal access codes that can be formed. 492,804 341,172 39,917,124 4,435,236