Prove: The square of a number that is two more than a multiple of 3 is one more
than a multiple of 3.
(3n + 2)2 = 9n2 + 12n + [?]
In²+ [
+1
In²+
+ [
In+])+1
=
n +
= 1 more than a multiple of 3

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

a

b

d

step-by-step explanation:

wow ok so the answer is 1k or just k

because of combining like terms xd