Mathematics, 14.05.2021 23:30 krisayon8126
Si se considera como aproximación válida que √2 = 1,41 y que √3 = 1.73, entonces aproximar por defecto a la centésima el valor de √24 se obtiene:
Answers: 2
Mathematics, 21.06.2019 19:00
What are the solutions of the equation? 6x^2 + 11x + 4 = 0 a. 4/3, 1/2 b. -4/3, -1/2 c. 4/3, -1/2 d. -4/3, 1/2
Answers: 2
Mathematics, 21.06.2019 19:20
Will give brainliest immeadeately true or false: the origin woud be included in the solution set for the inequality: y< 2x-5
Answers: 1
Mathematics, 21.06.2019 19:30
Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.
Answers: 1
Si se considera como aproximación válida que √2 = 1,41 y que √3 = 1.73, entonces aproximar por defec...
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