A particular automatic sprinkler system has two different types of activation devices for each sprinkler head. One type has a reliability of 0.89; that is, the probability that it will activate the sprinkler when it should is 0.89. The other type, which operates independently of the first type, has a reliability of 0.79. If either device is triggered, the sprinkler will activate. Suppose a fire starts near a sprinkler head. What is the probability that the sprinkler head will be activated

0.70

Step-by-step explanation:

Let the event A be "the first device is triggered" and the event B be "the second device is a".  We can state each probability as:

P(A) = 0.89

P(B) = 0.79

We want to determine the probability that the sprinkler head is activated given any of the devices is triggered, that is, P(A ∩ B).

For independent events, we have:

P(A ∩ B) = P(A) × P(B)

P(A ∩ B) = 0.89 × 0.79 = 0.70

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars