I need the answer fast pls

C. A = 0.5*d1*d2

D. A = bh

Step-by-step explanation:

The area of the rhombus can be found depending on what information is made available to us.

If given the lengths of the two diagonals (d1 and d2) of a rhombus which bisect each other, therefore, the formula for finding the area would be:

A = 0.5*d1*d2

Also, if we are given the height (h) and side (b), the formula to use would be:

A = bh

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2