Find the equation of the line parallel to y=-11-5, that passes through the point (4, -3). Write your answer in slope-intercept form. Do not use spaces in your
answer. Enter any fractions like a/b or-a/b.

y=41−11x

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

y=41−11x.

y=41−11x

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a