If a Variable has a normal distribution with mean 30 and standard deviation 5 find the probability that the variable will be between 25 and 37. A. 0.77
B. 80
0.72
0.75

P(25 < x < 37) = 0.77

Step-by-step explanation:

Given - If a Variable has a normal distribution with mean 30 and standard deviation 5

To find - find the probability that the variable will be between 25 and 37.

Proof -

Given that,

Mean, μ = 30

S.D, σ = 5

Now,

~ N(0,1)

Now,

P(25 < x < 37)

=

= P(1 < z < 1.4)

= P(z < 1.4) - P(z < -1)

= 0.9192 - 0.1587

= 0.7605

≈ 0.77

∴ we get

P(25 < x < 37) = 0.77

the answer is 48m^2!

step-by-step explanation: