PLEASE HELP ME, LIKE ACTUALLY! The sum of two numbers is 193. One of them in 71 more than the other. Find the larger of these two numbers

132

Step-by-step explanation:

X is smaller number

x + 71 is larger number.

x+ (x+71)=193

2x = 193-71

2x=122

x=61

x+71=largest number

61+71=132 largest numher

check answer

x+(x+71)=193

61+132=193

The larger of the two numbers is 132.

Step-by-step explanation:

let x be the larger number and y be the smaller number.

x + y = 193 [Equatio#1]

x = y +71 [Equation#2]

substitute x from equation #2 into equation # 1:

(y+71) + y = 193

2y = 193 - 71

2y = 122

y = 61

substitute this value of y back into equation #2 to solve for x:

x = (61)+71

x= 132

the larger number is 132.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option