Here is my question please anwser as soon as possible

is it asking which one is a y coordinate?

Q'(5, -3), R'(4, -1), S'(0, -2), T'(0, -5)

Step-by-step explanation:

Reflecting across the y-axis causes the x coordinate of a point to change to its opposite. So in terms of x and y: (x, y) ⇒ (-x, y)

Q(-5, -3) ⇒ Q'(5, -3)

R(-4, -1) ⇒ R'(4, -1)

S(0, -2) ⇒ S'(0, -2)

T(0, -5) ⇒ T'(0, -5)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this