A pentagon ABCDE has vertices located at A(-2, 6), B(-4, 3), C(-1, 1), D(2, 2), and E(2, 6). Max thinks that AE = DE. Which of the following is true? A. Max is incorrect. AE = 8 units, and DE = 4 units.
B. Max is incorrect. AE = 4 units, and DE = 8 units.
C. Max is correct. AE = 8 units, and DE = 8 units.
D. Max is correct. AE = 4 units, and DE = 4 units.

am busy Now I will do that later

do you have the measurements?

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.