Find the zeros of the function below, algebraically. f(x)=(x-2)^2-64

Please show how you got answer and explain :D

x=10 and x=-6

Step-by-step explanation:

f(x)=(x-2)²-64 (Given)

0=(x-2)²-64 (Set equation equal to 0)

64=(x-2)² (Add 64 to both sides)

±8=x-2 (Take the square root of both sides)

Because there are two possible roots, make 2 equations to find both:

8=x-2 and -8=x-2

10=x and -6=x

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b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.