A flagpole stands perpendicular to the ground. It is supported by a 20-foot cable that runs from the top of the flagpole to the ground at a point that is 12 feet from the base of the pole. Find the height of the flagpole. The Pythagorean theorem is a2 b2

h  =  16 feet

Step-by-step explanation:

Pythagoras´ theorem establishes, that in a right triangle square of the hypothenuse (c²) is the sum of leg ( b²)  plus  leg  (a²)

Then

c²  =  a²  +  b²

where according to the problem statement

(20)²  =  h²  +  (12)²           (  h is the height of the flagpole )

h²  =  400 -  144

h²  =  256

h  =  √ 256

h  =  16 feet

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.