A sample of a radioactive isotope had an initial mass of 690 mg in the year 1997 and decays exponentially over time. A measurement in the
year 2001 found that the sample's mass had decayed to 390 mg. What
would be the expected mass of the sample in the year 2011, to the
nearest whole number?

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Step-by-step explanation:

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its 94 on deltamath just did it

Step-by-step explanation:

Let t=0 represent the year 1997

Starting Value: 690

Write function:

y=690(b)^t

Now find the b-value:

y=390 when t=4 (2001−1997)

390=690(b)^4

390/690=690(b)^4/690

0.56521739=b^4

(0.56521739)^1/4=(b^4)^1/4

0.86706944=b

Write Complete Function:

y=690(0.86706944)^t

Find value in 2011 (use t=14):

y=690(0.86706944)^14

y=93.67062063

y≈94

unpaid balance is : $149.99-$50 = $99.99 new balance = 149.99+2.62-50 = $102.61 finance charge = 99.99- 0.21/12= $1.75 new balance = 99.99+1.75 = $101.74 average daily balance method average daily balance= 3399.70/30 = $113.32 finance charge = $ 0.21/12ă—113.32 = $1.98 new balance = $149.99-50+1.98 = $101.97

i understand 100% 10/10 hit or miss?

step-by-step explanation: