A jar contains 3 blue marbles and 2 red marbles. A marble is randomly selected from the jar and replaced, and then a second marble is chosen. What is the probability that the blue marble was chosen both times?​

3/5

Step-by-step explanation:

3+2=5. 3/5 is the blue marble. You may also say 6/10. It is likely you will pull out a blue marble.

step-by-step explanation:

im not sure what the answer is

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0