Sin a _ = 1/2[sin(a+b) +sin(a-b)]
A. sin b
B. cosa
C. sina
D. cosb
...
Mathematics, 19.05.2021 02:30 hayleneolide
Sin a _ = 1/2[sin(a+b) +sin(a-b)]
A. sin b
B. cosa
C. sina
D. cosb
![Sin a ____ = 1/2[sin(a+b) +sin(a-b)]
A. sin b
B. cosa
C. sina
D. cosb](/tpl/images/2362/5465/3e469.jpg)
Answers: 2
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